Added 15 solutions
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import java.io.*;
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import java.util.*;
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public class Solution {
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/* Runtime: O(n) using a HashMap */
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static boolean isAnagram(String a, String b) {
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if (a == null || b == null || a.length() != b.length()) {
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return false;
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}
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a = a.toLowerCase();
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b = b.toLowerCase();
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HashMap<Character, Integer> map = new HashMap<>();
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/* Fill HashMap with 1st String */
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for (int i = 0; i < a.length(); i++) {
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char ch = a.charAt(i);
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if (map.containsKey(ch)) {
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map.put(ch, map.get(ch) + 1);
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} else {
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map.put(ch, 1);
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}
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}
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/* Compare 2nd String to 1st String's HashMap */
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for (int i = 0; i < b.length(); i++) {
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char ch = b.charAt(i);
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if (map.containsKey(ch) && map.get(ch) > 0) {
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map.put(ch, map.get(ch) - 1);
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} else {
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return false;
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}
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}
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return true;
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}
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public static void main(String[] args) {
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Scanner scan = new Scanner(System.in);
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String a = scan.next();
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String b = scan.next();
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scan.close();
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boolean ret = isAnagram(a, b);
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System.out.println( (ret) ? "Anagrams" : "Not Anagrams" );
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}
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}
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